Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.1 - Angles and Polygons - Exercise - Page 388: 19


a. yes. b. yes.

Work Step by Step

a. We know that $\angle 2=\angle 3$ because they are alternate-interior angles, so $\angle 2=38^o$. Now $\angle 1+\angle 2=52^o+386^o=90^o$. That is $x\perp b$ and since $a\parallel b$, then $x\perp a$. b. As explained in (a), $x\perp b$.
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