Answer
1
Work Step by Step
Since $j=\sqrt{-1}$, $j^2=-1$, and $j^4=1$, we have
$$ j^{28}=(j^{4} )^7=1$$
where we used the fact that $28=4\times 7$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Test - Page 380: 16
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
