Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Test - Page 380: 15

Answer

$j$

Work Step by Step

Since $j=\sqrt{-1}$, $j^2=-1$, and $j^4=1$, we know that $j^8=(j^4)^2=1^2=1$ and we have $$ j^{9}=j^{8} j=j$$ where we used the fact that $9=4\times 2+1$
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