Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.4 - Special Products - Exercise: 37

Answer

$y^6-10y^3+25$

Work Step by Step

RECALL: $(a-b)^2=a^2-2ab+b^2$ Use the formula above to have: $(y^3-5)^2 \\=(y^3)^2-2(y^3)(5)+5^2 \\=y^6-10y^3+25$
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