Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Appendix B - Exponential Equations - Exercise - Page 577: 26

Answer

$$\approx 0.023.$$

Work Step by Step

We use the given decay formula: $y=y_oe^{-0.0045t}$ Where $y_o$ is the initial amount and $t$ is the time. By substitution, we have $$y=y_oe^{-0.045t}=75e^{-0.045\cdot 3\cdot 60}\approx 0.023.$$
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