Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Appendix B - Exponential Equations - Exercise - Page 577: 24

Answer

$$ 847~mV$$

Work Step by Step

We use the given exponential growth formula: $V=V_oe^{0.025t}$ Where $V_o$ is the initial amount and $t$ is the time. We substitute $t=45 \ ms$ and $V_0=275 \ mV$: $$V=V_oe^{0.025t}=275 e^{0.025\cdot 45}\approx 847~mV$$
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