Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.2 - Solving Quadratic Equations by Completing the Square - Exercise Set - Page 638: 14

Answer

$x=-2$

Work Step by Step

The coefficient of x is 6. Adding the square of half the coefficient of x creates a perfect square. $(6\div2)^2=3^2=9$ $x^2+6x=-8$ Add the square of half the coefficient of x to each side of the equation. $x^2+6x+9=-8+9$ Simplify. $x^2+6x+9=1$ Factor the polynomial. $(x+3)^2=1$ Take the square root of each side. $\sqrt{(x+3)^2}=\sqrt 1$ Simplify. $x+3=1$ Subtract 3 from each side. $x+3-3=1-3$ Simplify. $x=-2$
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