Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.1 - Finding Roots - Exercise Set: 84

Answer

$x\leq4$

Work Step by Step

For $\sqrt{8-2x}$ to be a real number, $8-2x$ must be non-negative. $8-2x\geq0$ Add 2x to both sides of the inequality and simplify. $8-2x+2x\geq0+2x$ $8\geq2x$ Divide both sides of the inequality by 2 and simplify. $8\div2\geq2x\div2$ $4\geq x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.