## Introductory Algebra for College Students (7th Edition)

$x\leq4$
For $\sqrt{8-2x}$ to be a real number, $8-2x$ must be non-negative. $8-2x\geq0$ Add 2x to both sides of the inequality and simplify. $8-2x+2x\geq0+2x$ $8\geq2x$ Divide both sides of the inequality by 2 and simplify. $8\div2\geq2x\div2$ $4\geq x$