# Chapter 8 - Section 8.1 - Finding Roots - Exercise Set: 81

all real numbers

#### Work Step by Step

For $\sqrt{x^2+2}$ to be a real number, $x^2+2$ must be non-negative. $x^2+2\geq0$ Subtract 2 from both sides of the inequality and simplify. $x^2+2-2\geq0-2$ $x^2\geq-2$ Since $x^2$ is always non-negative, the expression is true for all real number values of x.

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