Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Review Exercises - Page 619: 21



Work Step by Step

We can use the product rule for square roots to rewrite the two radicals as a single radical, a product of the two radicands: $$(\sqrt 3)(\sqrt 12) = \sqrt (3\times12)$$ We multiply the factors in the radicand to get: $$\sqrt 36$$ Since $36$ is a perfect square, we can simplify this radical by taking the square root of $36$, which is $6$: $$6$$
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