Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Review Exercises - Page 619: 14

Answer

$$3x\sqrt 7$$

Work Step by Step

We can use the product rule for square roots to rewrite the radicand as a product of the greatest perfect square factor and another factor. We can see that the radicand $63x^3$ can be broken down into two factors: the perfect square $9x^2$ and $7$: $$(\sqrt 9x^2)(\sqrt 7)$$ Because $9x^2$ is a perfect square, we go ahead and simplify the expression by taking the square root of $9x^2$, which is $3x$: $$3x\sqrt 7$$
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