Answer
Makes sense.
Work Step by Step
To subtract rational expressions with the same denominator,
subtract numerators and place the difference over the common denominator.
$...=\displaystyle \frac{(x-3)-(3x-5)}{x-1}$
$=\displaystyle \frac{x-3-3x+5}{x-1}$
$=\displaystyle \frac{-2x+2}{x-1}\qquad$... factor out $-2$ in the numerator
$=\displaystyle \frac{-2(x-1)}{(x-1)}\qquad$... common factors cancel,
$=\displaystyle \frac{-2}{1}=-2$
which is a constant.
Makes sense.
