Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.3 - Adding and Subtracting Rational Expressions with the Same Denominator - Exercise Set - Page 508: 79

Answer

Both problems are sums involving common denominators. To add fractions or rational expressions with the same denominator, add numerators and place the sum over the common denominator. Fractions: $\displaystyle \frac{3}{8}+\frac{1}{8}=\frac{4}{8}$ Rational expressions: $\displaystyle \frac{x}{x^{2}-1}+\frac{1}{x^{2}-1}=\frac{x+1}{x^{2}-1}$ Also, both problems have common factors in the numerators and denominators. Both can be reduced: Fractions: $\displaystyle \frac{4}{8}=\frac{4}{4\times 2}=\frac{1}{2}$ Rational expressions: $\displaystyle \frac{x+1}{x^{2}-1}=\frac{(x+1)}{(x+1)(x-1)}=\frac{1}{x-1}$

Work Step by Step

Both problems are sums involving common denominators. To add fractions or rational expressions with the same denominator, add numerators and place the sum over the common denominator. Fractions: $\displaystyle \frac{3}{8}+\frac{1}{8}=\frac{4}{8}$ Rational expressions: $\displaystyle \frac{x}{x^{2}-1}+\frac{1}{x^{2}-1}=\frac{x+1}{x^{2}-1}$ Also, both problems have common factors in the numerators and denominators. Both can be reduced: Fractions: $\displaystyle \frac{4}{8}=\frac{4}{4\times 2}=\frac{1}{2}$ Rational expressions: $\displaystyle \frac{x+1}{x^{2}-1}=\frac{(x+1)}{(x+1)(x-1)}=\frac{1}{x-1}$
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