Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 464: 139



Work Step by Step

$4x^{4}-9x^{2}+5$ ... Searching for two factors of $ac=20$ whose sum is $b=-9,$ we find$\qquad-4$ and $-5.$ Rewrite the middle term and factor in pairs: $=4x^{4}-4x^{2}-5x^{2}+5=$ $=4x^{2}(x^{2}-1)-5(x^{2}-1)$ $=(4x^{2}-5)(x^{2}-1)\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ =$(4x^{2}-5)(x-1)(x+1)$
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