Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.5 - A General Factoring Strategy - Exercise Set - Page 464: 138



Work Step by Step

$ 5y^{5}-5y^{4}-20y^{3}+20y^{2}\qquad$...factor in pairs. $=(5y^{5}-5y^{4})+(-20y^{3}+20y^{2})$ $=5y^{4}(y-1)-20y^{2}(y-1)\qquad$...factor out the common expression $=(y-1)(5y^{4}-20y^{2})\qquad$...factor again $=(y-1)[5y^{2}(y^{2}-4)]\qquad$...recognize the difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $=(y-1)[5y^{2}(y-2)(y+2)]$ $=5y^{2}(y-1)(y-2)(y+2)$
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