Answer
$(3w-4)(2w-1) $
Work Step by Step
Factoring by grouping:
1. Multiply the leading coefficient, a, and the constant, c.
2. Find the factors of ac whose sum is b.
3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2.
4. Factor by grouping
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Always start by searching for a GCF ... (there are none other than 1).
1. $\quad ac=+24$
2. $\quad$sum = $-11 \quad$... factors: $-8$ and $-3$
3. $\quad$ $6w^{2}-11w+4=(6w^{2}-8w)+(-3w+4)$
4. $\quad$... $=2w(3w-4) +(-1)(3w-4) =(3w-4)(2w-1)$
Check by FOIL
$F:\quad 6w^{2}$
$O:\quad -3w$
$I:\quad -8w$
$L:\quad +4$
$(3w-4)(2w-1) $ = $6w^{2}-11w+4$
