Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 443: 16



Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- Always start by searching for a GCF ... (there are none other than 1). 1. $\quad ac=+15$ 2. $\quad$sum = $-8 \quad$... factors: $-5$ and $-3$ 3. $\quad 5y^{2}-8y+3=(5y^{2}-5y)+(-3y+3)$ 4. $\quad$... $=5y(y-1)+(-3)(y-1) =(y-1)(5y-3)$ Check by FOIL $F:\quad 5y^{2}$ $O:\quad -3y$ $I:\quad -5y$ $L:\quad +3$ $(y-1)(5y-3)$ = $5y^{2}-8y+3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.