Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Review Exercises - Page 480: 66



Work Step by Step

$ 2y^{3}-16\qquad$...factor out the common term, $2$. $=2(y^{3}-8)\qquad$...use the difference of two cubes: $\mathrm{A}^{3}-\mathrm{B}^{3} = (\mathrm{A}-\mathrm{B})(\mathrm{A}^{2} + \mathrm{A}\mathrm{B} + B^{2})$ $=2((y)^{3}-(2)^{3})$ $=2(y-2)(y^{2}+2y+4)$
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