Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Review Exercises - Page 480: 62



Work Step by Step

$-10x^{5}+44x^{4}-16x^{3}\qquad$...factor out the common term, $-2x^{3}$ $=-2x^{3}(5x^{2}-22x+8)$ ... Searching for two factors of $ac=40$ whose sum is $b=-22,$ we find$\qquad-20$ and $-2.$ Rewrite the middle term and factor in pairs: $=-2x^{3}(5x^{2}-20x-2x+8)=$ $=-2x^{3}[5x(x-4)-2(x-4)]$ =$-2x^{3}(x-4)(5x-2)$
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