Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set - Page 408: 22



Work Step by Step

Using $x^{-a}=\dfrac{1}{x^a}$ the given expression, $ \left( \dfrac{3}{4} \right)^{-3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{1}{\left( \dfrac{3}{4} \right)^{3}} \\\\= \dfrac{1}{\left( \dfrac{27}{64} \right)} \\\\= 1\div\dfrac{27}{64} \\\\= 1\cdot\dfrac{64}{27} \\\\= \dfrac{64}{27} .\end{array}
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