Answer
$\dfrac{5}{6}$
Work Step by Step
Using $x^{-a}=\dfrac{1}{x^a}$the given expression, $
2^{-1}+3^{-1}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{1}{2^1}+\dfrac{1}{3^1}
\\\\=
\dfrac{1}{2}+\dfrac{1}{3}
\\\\=
\dfrac{3}{6}+\dfrac{2}{6}
\\\\=
\dfrac{5}{6}
.\end{array}
