Answer
$x^2+4x+4$
Work Step by Step
The length of the painting is $x$ and the frame adds $1+1=2$ inches. The width of the painting is $x$ and the frame adds $1+1=2$ inches.
Thus, the bigger rectangle has $l=x+2$ and $w=x+2.$ Therefore, the area of the bigger rectangle is
$A=lw=(x+2)(x+2)=x^2+4x+4.$
