Answer
$6x-12$
Work Step by Step
$(x+5)(x-6)$= mutiply each term of the second binomial with each term of the first
... (use the FOIL method)
$=x^{2}-6x+5x-30\qquad$... combine like terms
$=x^{2}-x-30\qquad (*)$
$(x+2)(x-9)$= use the same method as above.
$=x^{2}-9x+2x-18$
$=x^{2}-7x-18\qquad (**)$
$(*)-(**)=(x^{2}-x-30)-(x^{2}-7x-18)$
... distribute - take down the parentheses
$=x^{2}-x-30-x^{2}+7x+18$
... combine like terms
$=(x^{2}-x^{2})+(-x+7x)+(-30+18)$
$=0+6x-12$
= $6x-12$
