Answer
$16y+32$
Work Step by Step
We apply the square binomial formulas:
$(a+b)^2=a^2+2ab+b^2$
$(a-b)^2=a^2-2ab+b^2$
$(y+6)^2-(y-2)^2$
$=(y^2+12y+36)-(y^2-4y+4)$
$=y^2+12y+36-y^2+4y-4$
$=16y+32$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set - Page 360: 99
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