## Introductory Algebra for College Students (7th Edition)

{($\frac{1}{2}$,-2)}
y=2x-3 Plug this value for y into the other equation y=-2x-1 2x-3=-2x-1 2x+2x-3=-2x+2x-1 4x-3=-1 4x-3+3=-1+3 4x=2 x=$\frac{2}{4}$ x=$\frac{1}{2}$ Plug this value for x into the first equation to find y y=2($\frac{1}{2}$)-3 y=1-3 y=-2 Therefore the solution is {($\frac{1}{2}$,-2)}