Introductory Algebra for College Students (7th Edition)

{($\frac{5}{2}$,3)}
y=2x-2 Plug this value for y into the other equation 6x+8y=39 6x+8(2x-2)=39 6x+16x-16=39 22x-16=39 22x-16+16=39+16 22x=55 x=$\frac{55}{22}$ x=$\frac{5}{2}$ Plug this value for x into the first equation to find y. y=2x-2 y=2($\frac{5}{2}$)-2 y=5-2 y=3 Therefore the solution is {($\frac{5}{2}$,3)}