Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set: 16

Answer

A=400$\pi$ ft$^2$$\approx$1257 ft$^2$ C=40$\pi$ ft$\approx$126 ft

Work Step by Step

r=$\frac{1}{2}$d r=$\frac{1}{2}$(40) r=20 A=$\pi$r$^2$ A=$\pi$(20)$^2$ A=400$\pi$ ft$^2$$\approx$1257 ft$^2$ C=$\pi$d C=$\pi$40 C=40$\pi$ ft $\approx$126 ft
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