Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.6 - Problem Solving in Geometry - Exercise Set: 15

Answer

A= 36$\pi$ yd$^2$$\approx$113 yd$^2$ C=12$\pi$ yd$\approx$38 yd

Work Step by Step

r=$\frac{1}{2}$d r=$\frac{1}{2}$(12) r=6 A=$\pi$r$^2$ A=$\pi$(6)$^2$ A=36$\pi$ yd$^2$$\approx$113 yd$^2$ C=$\pi$d C=$\pi$12 C=12$\pi$ yd $\approx$38 yd
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