Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.1 - The Addition Property of Equality - Exercise Set - Page 120: 37



Work Step by Step

Add $\frac{3}{2}$ to both sides of the equation to isolate the variable. -$\frac{3}{5}$=-$\frac{3}{2}$+s -$\frac{3}{5}$+$\frac{3}{2}$=s -$\frac{3(2)}{5(2)}$+$\frac{3(5)}{2(5)}$=s -$\frac{6}{10}$+$\frac{15}{10}$=s $\frac{9}{10}$=s s=$\frac{9}{10}$ Check the answer. -$\frac{3}{5}$=-$\frac{3}{2}$+($\frac{9}{10}$) -$\frac{3}{5}$=-$\frac{15}{10}$+$\frac{9}{10}$ -$\frac{3}{5}$=-$\frac{6}{10}$ -$\frac{3}{5}$=-$\frac{3}{5}$
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