Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.1 - The Addition Property of Equality - Exercise Set: 28

Answer

x=$\frac{13}{10}$

Work Step by Step

Add $\frac{3}{5}$ to both sides of the equation to isolate the variable. x-$\frac{3}{5}$=$\frac{7}{10}$ x=$\frac{7}{10}$+$\frac{3}{5}$ x=$\frac{7}{10}$+$\frac{6}{10}$ x=$\frac{13}{10}$ Check the answer. ($\frac{13}{10}$)-$\frac{3}{5}$=$\frac{7}{10}$ $\frac{13}{10}$-$\frac{6}{10}$=$\frac{7}{10}$ $\frac{7}{10}$=$\frac{7}{10}$
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