Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Mid-Chapter Check Point: 6

Answer

y=-$\frac{8}{9}$

Work Step by Step

1-3(y-5)=4(2-3y) 1-3(y)-3(-5)=4(2)+4(-3y) 1-3y+15=8-12y (1+15)-3y=8-12y 16-3y=8-12y 16-3y+12y=8 16+9y=8 9y=8-16 9y=-8 y=$\frac{-8}{9}$
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