Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Mid-Chapter Check Point - Page 155: 14



Work Step by Step

10($\frac{1}{2}$x+3)=10($\frac{3}{5}$x-1) 5x+10(3)=6x-10(1) 5x+30=6x-10 5x+30+10=6x 5x+40=6x 40=6x-5x 40=x x=40
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