Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Cumulative Review Exercises - Page 207: 3

Answer

-128

Work Step by Step

(8-10)$^3$(7-11)$^2$ First subtract inside the two sets of parentheses. (-2)$^3$(-4)$^2$ Then solve both exponents. (-2)(-2)(-2)(-4)$^2$ (-8)(-4)$^2$ (-8)(-4)(-4) (-8)(16) Then multiply. -128
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