Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Cumulative Review Exercises - Page 207: 12


$$x = -6$$

Work Step by Step

To solve the equation, we need to isolate $x$. In this problem, we want to multiply by the least common denominator to get rid of the fractions first. The least common denominator for all terms is $15$: $$15(\frac{x}{5}) - 15(2) = 15(\frac{x}{3})$$ Divide out common denominators to get rid of the fractions: $$3x - 30 = 5x$$ Subtract $3x$ from each side of the equation to isolate the variable on one side of the equation: $$5x = -30$$ Divide each side by $5$ to isolate $x$: $$x = -6$$
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