Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Test - Page 111: 23


not a solution

Work Step by Step

Plug in 3 for x and simplify to see if the equation is true or false. $\frac{1}{5}$(x+2)=$\frac{1}{10}$x+$\frac{3}{5}$ $\frac{1}{5}$(3+2)=$\frac{1}{10}$(3)+$\frac{3}{5}$ $\frac{1}{5}$(5)=$\frac{1}{10}$(3)+$\frac{3}{5}$ 1=$\frac{1}{10}$(3)+$\frac{3}{5}$ 1=$\frac{3}{10}$+$\frac{3}{5}$ 1=$\frac{3}{10}$+$\frac{3(2)}{5(2)}$ 1=$\frac{3}{10}$+$\frac{6}{10}$ 1$\ne$$\frac{9}{10}$ This is not a solution.
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