Answer
$150$
Work Step by Step
Substitute $-10$ to $x$ to obtain:
$=(-10)^2-5(-10)
\\=(-10)(-10)-(-50)
\\=(-10)(-10)+50$
The product of two negative integers is positive.
Simplify to obtain:
$=100+50
\\=150$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 1 - Test - Page 111: 18
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