Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.4 - Basic Rules of Algebra - Exercise Set - Page 54: 77


$a.\quad U=10n+137$ $b.\quad $257 million, exact value

Work Step by Step

a. $ U=4(2n+32)+2(n+\displaystyle \frac{9}{2})\qquad$... distribute $ U=(8n+128)+(2n+9)\qquad$... get rid of parentheses $ U=8n+128+2n+9\qquad$...rearrange and group like terms $U=(8n+2n)+(128+9)$ $U=10n+137$ b. In 2012 (12 years after 2000), $n=12$. Substituting, $U=10(12)+137$ $=120+137$ $=257$ (million) The same value is shown on the graph, so the model gives the exact value for 2012.
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