## Introductory Algebra for College Students (7th Edition)

$8+5(x-1)$, simplifies to $\quad 5x+3$
"eight increased by"$\quad\rightarrow 8+...$ " the product of 5 and ..."$\quad\rightarrow 5\cdot(...)$ "one less than a number"$\quad\rightarrow (x-1)$ the expression translates to$:\qquad 8+5(x-1)$ Using the distributive property, $8+5(x-1)=8+5x-5\cdot 1$ $=8+5x-5$ ... group like terms (8 and 5x can change places) $=5x+(8-5)$ = $5x+3$