## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Mid-Chapter Check Point - Page 55: 7

Not a solution

#### Work Step by Step

Plug in $\frac{3}{4}$ for y and then simplify to see if the equation is true or false. 8y=12(y-$\frac{1}{2}$) 8($\frac{3}{4}$)=12($\frac{3}{4}$-$\frac{1}{2}$) $\frac{24}{4}$=12($\frac{1}{4}$) 6$\ne$3 This equation is false therefore this is not a solution.

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