Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Mid-Chapter Check Point: 11

Answer

$\frac{25}{66}$

Work Step by Step

$\frac{5}{22}$+$\frac{5}{33}$ $\frac{5\times3}{22\times3}$+$\frac{5\times2}{33\times2}$ $\frac{15}{66}$+$\frac{10}{66}$=$\frac{25}{66}$
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