Answer
$1$
Work Step by Step
RECALL:
(i) $\log_b{b} = 1$
(ii) $\log_b{1}=0$
(iii) $\log_b{b^x} = x$
Write $32$ as $2^5$ to obtain:
$=\log_5{(\log_2{2^5})}$
With $b=2$ and $x=5$, use rule (iii) to obtain:
$\log_5{(\log_2{2^5})}=\log_5{5}$
Use rule (i) above to obtain:
$\log_5{5}=1$