## Intermediate Algebra for College Students (7th Edition)

$1$
RECALL: (i) $\log_b{b} = 1$ (ii) $\log_b{1}=0$ (iii) $\log_b{b^x} = x$ Write $32$ as $2^5$ to obtain: $=\log_5{(\log_2{2^5})}$ With $b=2$ and $x=5$, use rule (iii) to obtain: $\log_5{(\log_2{2^5})}=\log_5{5}$ Use rule (i) above to obtain: $\log_5{5}=1$