## Intermediate Algebra for College Students (7th Edition)

$0$
RECALL: $\ln{1}=0$ (refer to page 698 of the textbook) Thus, the given expression is equal to 0. An alternate solution would be: RECALL: $\ln{x} = y \longrightarrow e^y=x$ Thus, $\ln{1} =y\longrightarrow e^y=1$ Note that $e^0=1$. Replace $1$ with $e^0$ to obtain: $e^y = e^0$ Use the rule "If $a^m=a^n$, then $m=n$" to obtain: $y=0$ Therefore $\ln{1}=y=0$