Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.1 - Exponential Functions - Exercise Set - Page 675: 83

Answer

The solution set is $\{-2,5\}$.

Work Step by Step

The given expression is $x(x-3)=10$ Clear the parentheses. $x^2-3x=10$ Subtract $10$ from both sides. $x^2-3x-10=10-10$ Simplify. $x^2-3x-10=0$ Factor $x^2-5x+2x-10=0$ $x(x-5)+2(x-5)=0$ $(x-5)(x+2)=0$ Set each factor equal to zero. $x-5=0$ or $x+2=0$ Isolate $x$. $x=5$ or $x=-2$.
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