Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.1 - Exponential Functions - Exercise Set - Page 675: 81

Answer

$b=\frac{aD}{a-D}$

Work Step by Step

$D=\frac{ab}{a+b}\\D(a+b)=ab\\Da+Db=ab\\Da=ab-Db\\aD=b(a-D)\\b=\frac{aD}{a-D}$
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