Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Concept and Vocabulary Check - Page 607: 4

Answer

$ x= 2±2\sqrt 2$

Work Step by Step

$x=\frac{-(-4)\sqrt{(-4)^2-4(1)(2)}}{2(1)}$ $x=\frac{4\sqrt{16-8}}{2}$ $x = \frac{4±\sqrt8}{2}$ $ x= 2±\sqrt {4⋅2}$ $ x= 2±2\sqrt 2$
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