Answer
FALSE. The equation with solution set {$2,5$} is $(x - 2)(x - 5) = 0$.
Work Step by Step
FALSE
Plug in the roots $𝛼=2$ and $𝛽=5$ to the quadratic equation: $x^2−(𝛼+𝛽)x+𝛼𝛽=0$
$x^2−(2+5)x+(2⋅5)=0$
$x^2−7x+10=0$ which can be factored into:
$(x-2)(x-5)$
$(x - 2)(x - 5) = 0$
