#### Answer

$(x - 1)^2 = 16$
Using the Square Root Property, $u^2 = d$, then $u = \sqrt d$ or $u = - \sqrt d$.
In this case,
$u^2 = (x-1)^2$ and $d = 16$
Thus,
$x-1 = ±\sqrt 16$
$x = 1± 4$
$x = 5$ or $x = -3$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

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