Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 595: 100

Answer

Does not make sense. Take for example the equation: $x^2 - bx = c$ Adding a negative constant will only affect the constant term $c$, and will not get you closer to completing the square. It will, in fact, give you an equation where you still need to isolate the binomial term. $x^2 - bx -c = c -c$ $x^2 - bx -c = 0$ Instead, what you need to do is to get the square of half the value of the coefficient of the $x$-term, and add this on both sides to complete the square. $x^2 - bx + (\frac{-b}{2})^2= c +(\frac{-b}{2})^2$

Work Step by Step

Does not make sense. Take for example the equation: $x^2 - bx = c$ Adding a negative constant will only affect the constant term $c$, and will not get you closer to completing the square. It will, in fact, give you an equation where you still need to isolate the binomial term. $x^2 - bx -c = c -c$ $x^2 - bx -c = 0$ Instead, what you need to do is to get the square of half the value of the coefficient of the $x$-term, and add this on both sides to complete the square. $x^2 - bx + (\frac{-b}{2})^2= c +(\frac{-b}{2})^2$
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