Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 593: 68


$d = \sqrt\frac{kP_{1}P_{2}}{C}$

Work Step by Step

$C = \frac{kP_{1}P_{2}}{d^2}$. Solve for $d$. $Cd^2 = kP_{1}P_{2}$ $d^2 = \frac{kP_{1}P_{2}}{C}$ $d = \sqrt\frac{kP_{1}P_{2}}{C}$
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