Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.1 - The Square Root Property and Completing the Square - Exercise Set - Page 593: 37


{$-3-\sqrt {7},-3+\sqrt {7}$}

Work Step by Step

Given: $x^2+6x=-2$ We need to add $3^2$ to complete the square. Thus, $x^2+6x+3^2=-2+9$ or, $x^2+(2)(1)(3x)+3^2=7$ or, $(x+3)^2=7$ or, $(x+3)=\pm \sqrt {7}$ or, $x=-3- \sqrt {7},-3+\sqrt {7}$ Hence, solution set is $x=${$-3-\sqrt {7},-3+\sqrt {7}$}
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